How is this equation completed? i cannot find any examples in the book.


How is this equation completed? i cannot find any examples in the book.

Answers: 1

Answers

  • Answer posted by: aroland1990x

    Option D

    t_{max} =19\ s

    Step-by-step explanation:

    Note that the projectile height as a function of time is given by the quadratic equation

    h = -12t ^ 2 + 456t

    To find the maximum height of the projectile we must find the maximum value of the quadratic function.

    By definition the maximum value of a quadratic equation of the form

    at ^ 2 + bt + c is located on the vertex of the parabola:

    t_{max}= -\frac{b}{2a}

    Where a

    In this case the equation is: h = -12t ^ 2 + 456t

    Then

    a=-12\\b=456\\c=0

    So:

    t_{max} = -\frac{456}{2*(-12)}

    t_{max} =19\ s

  • Answer posted by: ximena68

    fist on the left goes with the third on the right. second on the left goes with the fourth on the right. third on the left goes with the second on the right. the fourth on the left goes with first on the right

    Draw lines to match each expression on the left with the correct product on the right.
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How is this equation completed? i cannot find any examples in the book....

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